itsnavin
August 28th, 2002, 08:54 PM
Complete the series up to atleast 25 terms:
3,3,5,4,4,3,5,5,4...
Hint: 29th term is 10, 39th is also 10 and 100th term is 7
Good luck...Cheers
saurabhsaharan
August 28th, 2002, 11:02 PM
3,3,5,4,4,3,5,5,4,3,6,6,8,8,7,7,9,8,8,6,9,9,11,
10,10,9,11,11,10,,,,and so on :)
yvsgaawar
August 28th, 2002, 11:23 PM
Wow!! Saurabh bhai you are Simply great.
naveenadalal
August 29th, 2002, 07:41 AM
Naveen & saurabh u both r doing great job,
Is this a team work by both of u as all puzzles asked by naveen & solved by saurabh ( just for kidding)
vaise to achha hi hai jo saurabh solve kar deta hai, apna to dimaag chalta hi nahi.(saurabh bhai lagta yeh hanumaan chalisa ka kamaal hai).
itsnavin
August 29th, 2002, 01:10 PM
Mast...Saurabh Bandhu!
Good job...more to come...
saurabhsaharan
August 29th, 2002, 10:13 PM
Thanks Gaawar Bhai, Navin Bhai and Naveena Bhan!!
Explanation of solution:
This series contains the number of alphabets that appear in each successuve "number:
ONE = 3 (The word "ONE" contains 3 alphabets)
TWO = 3
THREE = 5
FOUR = 4
FIVE = 4
SIX = 3
....and so on
Saharan