Can u find any flaws??

[hamendra]

I Prove 3 = 2
Mail me the answer if you happen to find anything wrong...


Can U Prove 3=2 * * * * *??

This seems to be an anomaly or whatever u call in mathematics.

It seems, Ramanujam found it but never disclosed it during his life time and that it has been found from his diary .

See this illustration:

-6 = -6

9-15 = 4-10

adding 25/4 to both sides:

9-15+(25/4) = 4-10+(25/4 )

Changing the order

9+(25/4)-15 = 4+(25/4)-10

(this is just like : a square + b square - two a b = (a-b)square.)

Here a = 3, b=5/2 for L.H.S and a =2, b=5/2 for R.H.S.

So it can be expressed as follows:

(3-5/2)(3-5/2) = (2-5/2)(2-5/2)

Taking positive square root on both sides:

3 - 5/2 = 2 - 5/2

3 = 2 ????????

[mukeshkumar007]

3 = 2 ????????

bhai Hamendra..yaa ganit mero weak point re....

[kismat.singh]

Hamendra,
The problem is towards the end when you take the square root and equate.
square(A) = sqaure(B) only means that |A| = |B| (i.e. either A=B or A=-B)
and not A = B ( for example square of 2 and -2 is same).

In the case you have taken, A = -B is correct (A=3-5/2 and B=2-5/2).
Hope I am correct.

Cheers,
Kismat

[ravichaud]

I think the last two lines require more explanation. Square root yields two possible answers (positive and negative). How were you able to get to the final line?

[ratananmol]

Taking the square root means multiplication (or division) by unequal numbers which does not retain the equality; this explains this fallacy.
I hope this has nothing to do with Ramanujan.
Cheers!

[arunshamli]

(3-5/2)(3-5/2) = (2-5/2)(2-5/2)

plus/minus(3-5/2)= plus/minus(2-5/2)

case 1.
+(3-5/2)=-(2-5/2)
3-5/2=-2+5/2
3=-2+5/2+5/2
3=-2+10/2
3=-2+5
3=3(which is TRUE)

case 2.
-(3-5/2)=+(2-5/2)
-3+5/2 = 2-5/2
-3+5/2+5/2=2
-3+10/2=2
-3+5=2
2=2(TRUE again)

in the original question above two different values are being equated...and that is the reason for the wrong answer....

[mbamal]

ok Harmendra,

Let me prove something else..

1 = SQRT(1)=SQRT(-1*-1)=SQRT(-1)*SQRT(-1)

now SQRT(-1)=i (imaginary number)

so RHS = i*i =-1

so 1 = -1, same way 3=2..lol...

basically u cannot factorize a positive real number into product of two -ve numbers inside a square root.. the value after the root in ur question should be 5/2-2 and not 2-5/2